Hello. Some monks and I were discussing perl 6, and BooK said, why not just %elbow = 1..10, 11..20;
So I test it out, like i do everything, and i do: perl -e"%a=( 1..10, 11..20 );print keys %a" and I get no output.

I try all my activeperl installs, nada. I try all my indigoperl installs, same thing (btw this be 5.6.0 and 5.6.1 builds 618 and up)

Meanwhile, BooK says, yes it does, and spits Dumper in the cb: perl -MData::Dumper -e'print { 1..10, 11..20 } and sure enough, Dumper dumps a hash like: 

$VAR1 = {
          '13' => 14,
          '7' => 8,
          '15' => 16,
          '9' => 10,
          '1' => 2,
          '17' => 18,
          '3' => 4,
          '19' => 20,
          '11' => 12,
          '5' => 6
        };

[download]

So I ssh over to jcwrens machine and sure enough i get some keys (111313515717919).

So now I says to me, this must be a bug, and to confirm, i try: perl -MData::Dumper -e "%a= 1 .. 10, 2 .. 11 ;print Dumper \%a" which yields nada, and then perl -MData::Dumper -e "$a={ 1 .. 10, 11.. 20};print Dumper $a" which spits our (as expected) 

$VAR1 = {
          '13' => 14,
          '7' => 8,
          '15' => 16,
          '9' => 10,
          '1' => 2,
          '17' => 18,
          '3' => 4,
          '19' => 20,
          '11' => 12,
          '5' => 6
        };

[download]
So, I think this is a win32 bug. Can anyone confirm/deny? Anyone have any idea where it is, sourcecode wise? (like foo.c or something)

 
___crazyinsomniac_______________________________________
Disclaimer: Don't blame. It came from inside the void
perl -e "$q=$_;map({chr unpack qq;H*;,$_}split(q;;,q*H*));print;$q/$q;"

In reply to perl -e hash assignment and range operator bug by crazyinsomniac

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