My attention was directed to the post to which this is a reply. I'm not quite sure what the point of that post is, or why it was brought to my attention. All I can say is: Of course '^something' is a single-quoted string literal.

That doesn't mean it the code doesn't result in a regex match. We already know it does. 

>perl -MO=Concise,-exec -e"$x =~ '^something'"
1  <0> enter
2  <;> nextstate(main 1 -e:1) v:{
3  <#> gvsv[*x] s
4  </> match(/"^something"/) vKS/RTIME
5  <@> leave[1 ref] vKP/REFC
-e syntax OK

[download]

In reply to Re^3: Misreading m// documentation (perlop =~ ) by ikegami
in thread Misreading m// documentation by QM

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