Hi All,
I am wondering why $test1 the code below stays 0.
sub test{ my $i = shift; my $params = shift; my $test1 = $params->{test} if exists $params->{test}; print "test1 after hash assignment:\t\t$test1\n"; $test1 = $i if ! defined $test1; print "i = $i\ttest1 after defaulting to i:\t$test1\n"; } for my $i(0..3){ &test($i,{}); }

Output: Use of uninitialized value $test1 in concatenation (.) or string at te +st.pl line 19. test1 after hash assignment: i = 0 test1 after defaulting to i: 0 test1 after hash assignment: 0 i = 1 test1 after defaulting to i: 0 test1 after hash assignment: 0 i = 2 test1 after defaulting to i: 0 test1 after hash assignment: 0 i = 3 test1 after defaulting to i: 0 <br>

I figured out that the line my $test1 = $params->{test} if exists $params->{test}; causes the trouble, but I am wondering why.
Thanks!

In reply to postfix syntax enlightenment by RobertCraven

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