Running: 

use strict;
use warnings;

my @list  = ( "abc", "def" );
my $nelts = 3;

# Case 1
{
   my @arr = ( [@list] ) x $nelts;
   for my $e (@arr) { print "Case 1 before: $e: $e->[0] $e->[1]\n" }
   $arr[0]->[0] = "xyz"; $arr[0]->[1] = "123";
   for my $e (@arr) { print "Case 1 after : $e: $e->[0] $e->[1]\n" }
}

print "\n";

# Case 2
{
   my @arr = map { [@list] } 1 .. $nelts;
   for my $e (@arr) { print "Case 2 before: $e: $e->[0] $e->[1]\n" }
   $arr[0]->[0] = "xyz"; $arr[0]->[1] = "123";
   for my $e (@arr) { print "Case 2 after: $e: $e->[0] $e->[1]\n" }
}

[download]
produces: 
Case 1 before: ARRAY(0x61ddc8): abc def
Case 1 before: ARRAY(0x61ddc8): abc def
Case 1 before: ARRAY(0x61ddc8): abc def
Case 1 after : ARRAY(0x61ddc8): xyz 123
Case 1 after : ARRAY(0x61ddc8): xyz 123
Case 1 after : ARRAY(0x61ddc8): xyz 123

Case 2 before: ARRAY(0x61de28): abc def
Case 2 before: ARRAY(0x315918): abc def
Case 2 before: ARRAY(0x315990): abc def
Case 2 after: ARRAY(0x61de28): xyz 123
Case 2 after: ARRAY(0x315918): abc def
Case 2 after: ARRAY(0x315990): abc def

[download]
As you can see, Case 1 above produces a list of identical references (so that changing the value of the first item in the list results in all list values changing) while with Case 2 above, changing the value of the first item leaves the other list values unchanged. Now Case 2 is the behavior I wanted but I (foolishly) started with: 
my @arr = ( [@list] ) x $nelts;

[download]
... got surprised when changing one list element changed them all, so randomly switched to: 
my @arr = map { [@list] } 1 .. $nelts;

[download]
Since this is a fairly common operation, I was wondering if there is a "standard" way to do Case 2. How would you do it?

In reply to Surprised by repetition (x) operator applied to a list by eyepopslikeamosquito

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