my $conf = "$_";
I suspect the warning is coming from that line (which is not line 32 in the code you posted). I don't think you ever set the $_ special variable before you used it. Also, there is usually no reason to place quotes around a scalar variable. Also, what you get is a warning, not an error. It appears because you use warnings;, which is a good idea because it notifies you that there is something unexpected in your code.

The other errors you see are like due to coping with scoping.

In reply to Re: Use of uninitialized value $_ in string by toolic
in thread Use of uninitialized value $_ in string by juanpablo

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