fssize=$(df -k $fs | grep -v Filesystem | awk \'{print $2}\');

Same as:

fssize=$(df -k --output=size $fs);

(but probably a little slower that this last line...)

've tried and backticks and qx// and IPC::Run, and even open() but they all seem to have the same limitation - when I pass the hash element as the command to be executed it gets interpreted one line at a time

thus forget about the for loop, forget about the bash array and do all in one line

perl -e 'my $foo=`df -k --output=size /tmp /var /home`; $foo=~s/\n//g +; print "$foo\n";' returns --> 1K-blocks 12345 67890 1234567890

You can now manipulate the string $foo directly in perl


In reply to Re: Running blocks of shell script from within perl script by pvaldes
in thread Running blocks of shell script from within perl script by lilgreen

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