If I understand you correctly, you just want the contents of toFind and the contents of toReplace in the same log file, right? Would this work?

 $data =~ s/$_->{toFind}/Original line: $_->{toFind}\n Replace with: $_->{toReplace}\n/g foreach (@myHashArray);

But I confess I really don't know what you're doing or why you're doing it. Perhaps most importantly, you seem to make a distinction between "about 1200 files", and "a log file", but the code you have shown has no evidence of that (or, indeed, output of any kind). The $data =~ ... bit looks like it might be the original text replacement, but then where is the log file? Or is there another explanation entirely?

use strict; use warnings; omitted for brevity.

In reply to Re: array of hashes help by rjt
in thread array of hashes help by rv799cv

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