Consider the code: 
$h->{bar}=1;
print "$h $$h{bar}\n";

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It, as expected, outputs: 
HASH(0x7fefc8) 1

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Then consider the code: 
$h->{bar}=1;
$h='foo';
print "$h $$h{bar}\n";

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Although the code is somewhat nonsensical, it outputs the expected: 
foo

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What I want to know is where I can look in the perl docs to predict this behavior: 
$h='foo';
$h->{bar}=1;
print "$h $$h{bar}\n";

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Which outputs what more devout perl monks than I undoubedly expect: 
foo 1

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In reply to Implicit Reference Assignment Surprisingly Doesn't Overwrite Prior Scalar by jabowery

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