You're right, but note that @{[ sort @a ]} evaluates as an array, not a list ($a would contain '3', not 'c').

This is probably not a problem, since ZZamboni's code doesn't seem to want the last value from the sorted list. It is, however an entirely plausible reason to try:   (To get the last sorted value) scalar(sort @array)

This is just a bit of a bummer, since it forces some kinda ugly syntax to do something which ZZamboni's code feels like it should just naturally do. 

my @a = ('a','b','c');
print ((sort @a)[$#a]);

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Russ

In reply to RE: Re: scalar doesn't work values returned by a function? by Russ
in thread scalar doesn't work values returned by a function? by ZZamboni

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