Hi,

The demo:
#!perl -l use strict; use warnings; my $orig = 'a.dll'; my $replacement = 'b.dll'; my $str1 = "foo $orig bar"; my $str2 = $str1; $str1 =~ s/\Q$orig\E/\Q$replacement\E/g; $str2 =~ s/\Q$orig/$replacement/g; print $str1; print $str2;
I expected $str1 and $str2 to be identical after the substitution regexes, but they're not (on both perl-5.16.0 and 5.20.0 at least). For me, the demo outputs:
foo b\.dll bar foo b.dll bar
Why does the first regex put that backslash in there ?
Are we allowed a maximium of *one* \Q per regex ?
Is there documentation that explains this ?

Supposing that instead of the first regex, I had wanted to do:
$str1 =~ s/\Q$orig\E.+/\Q$replacement\E/g;
$str1 would then have become foo b\.dll, whereas I expected foo b.dll.

Cheers,
Rob

In reply to A misunderstanding of quotemeta ? by syphilis

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