You are correct, $a would equal 3 in my last bit of code,
because the sort will return a list and then store
it in a referenced array which is then dereferenced and cast into scalar context which finally returns the size of the array. Got it? Good.
I dont think I implied anything else though. I am not under the
impression that
ZZamboni wanted anything other than the
size of the sorted array, but maybe I am wrong.
If you wanted the last element of the sorted array of course you
would do
(sort @a)[-1]
I certainly would not guess that scalar(sort @a) would return the
last element, so I am glad that it doesnt, but apparently you think it should.
I suppose you could write your own sort routine to do that in scalar context, but I like it the way it is.
Just my opinion though.
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