Hi, Im trying to output some lines of input if they contain certain regexp, but am having trouble with the output file. I am using the code below:

if (-z BADSYMS ) {
         (`rm BADSYMS.out`);
           }
        else { print ("Bad symbols contained in BADSYMS.out\n"); }

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I want to test to see if the file is empty and if so remove it. Otherwise I want to print the name of it.

I am currently opening the file at the beginning of the script, as opposed to opening it only if the pattern is matched.

Am I using the -z incorrectly? I have also tried the -s by assigning it to a scalar and seeing if ==0 but this hasn't worked correctly either.

Any thoughts?

Thanks, Martin

In reply to -z file test operator by Anonymous Monk

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