Nope. If you want to know if string2 is in string1, you need string1 on the left side and string2 on the right side of the binding operator.
$ perl -E 'my $str1 = qq(one two three); my $str2 = qq(two); if ($str
+2 =~ m/$str1/) { say "foo";}'
$ perl -E 'my $str1 = qq(one two three); my $str2 = qq(two); if ($str
+1 =~ m/$str2/) { say "foo";}'
foo
Your test is wrong for the following reason: if you want to try to put string1 on the right side, then it is string1 that should be a
quotemetaed regex or have the pipes escaped:
$ perl -E 'my $str1 = qr(\|L\|D\|); my $str2 = qq(\|L\|); if ($str2 =
+~ m/$str1/) { say "foo";}'
$ perl -E 'my $str1 = qq(\|L\|D\|); my $str2 = qr(\|L\|); if ($str1 =
+~ m/$str2/) { say "foo";}'
foo
$ perl -E 'my $str1 = qq(|L|D|); my $str2 = qq(|L|); if ($str1 =~ m/\
+Q$str2/) { say "foo";}'
foo
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