Ah, you're using an ancient perl. Simply leave out the use feature qw/say/; line, and replace say; in the loop body with a print statement: 

while(<DATA>) {
    chomp;
    s/<([0-9A-F]+)>/hex($1)/eg;
    print "$_\n";
}

[download]

Actually, you could probably also get away with not chomping your input in the first place here: 

while(<DATA>) {
    s/<([0-9A-F]+)>/hex($1)/eg;
    print;
}

[download]

And at this point, assuming you merely want to output the results and do nothing further with them in this particular script, the whole script can be turned into a oneliner you can directly enter on the command line. Using perl's -p switch (see perlrun): 

$ perl -pe 's/<([0-9A-F]+)>/hex($1)/eg' /home/stummala/a
JDW-HP 1MVWV93V7j2Hxsa0Ag6 24:00:00 SUBJECT_EXACT _Did you160serve our
+160country? -New VA Home.Loan Program_
JDW-HP 1MVWV98Ddd4fLsa0Ag6 24:00:00 SUBJECT_EXACT Did.you.serve_our co
+untry? New-VA Home160Loan Program_
$

[download]

In reply to Re^5: How do i replace one variable with another after searching for a pattern by AppleFritter
in thread How do i replace one variable with another after searching for a pattern by Niklaus Mikaelson

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