how to exit the loop after complete 3 rounds...?? it means... if you enter 3 times wrong input it should exit from the program... here i am providing code please modify it 
#!/user/bin/perl
print"enter the rang of array:\n";
chomp($c=<STDIN>);
while($i=1){
print"while loop round:$i\n";
    if($i>3){
        exit;
    }
    if($c =~ /^\[|[a-z,A-Z]+/){
        print "it is invalid please enter digits\n";
        #print"enter the rang of array:\n";
        #chomp($c=<STDIN>);
    }
    elsif($c =~ /^[1-9]+/){
        print "you are entered correct input\n";
        last;
    }
$i++;
}
@a=();
$b;
$1;
print"Enter the array:\n";
for($i=0;$i<$c;$i++){
chomp($b=<STDIN>);
$a[$i]=$b;
}
#for($i=0;$i<@a;$i++){
#print"the array $a[$i]\n";
#}
#print"the PSI ID's:";
foreach $val(@a){
#print"####$val###\n";
    if($val=~ /^([a-z]+)\s?PSI\-ID\-?(\d+)/){
    print"value=$2\n";
    push(@b,$1);
    push(@c,$2);
    }
}
print"the pax id's with PSI:\n";
for($i=0;$i<=@b;$i++){
    for($j=0;$j<=@c;$j++){
        if($i==$j){
            print"$b[$i] $c[$j]\n";
        }
    }
}

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In reply to Re^2: Regex shows only last match multiple times? by Anonymous Monk
in thread Regex shows only last match multiple times? by GertMT

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