I guess that the point of the patch of japhy described Why Is $& Bad? is more efficient obfuscation :)

But I was surprised by what I got when I executed the following code (using perl 5.006001). I have not gone thru the Perl sources to explain the behavior. Or I am missing something obvious?

So I ask you to answer without executing it: 1/ Does it compile 2/ If so, what does it do?

open *&, "/etc/printcap";
print "opened\n" unless  eof( *&);
print <&>;

[download]

-- stefp

In reply to why is *& weird? by stefp

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