s/(\s*'[^']*?')//g;

I'm not sure why you enclose the pattern in parentheses as I don't think a capture is required. Also, you don't need the non-greedy quantifier when using negated character classes, that's the whole point of using them as it means you can avoid the commonly seen .*? pattern.

I hope this is of interest.

Cheers,

JohnGG

In reply to Re^2: strip text from a string by johngg
in thread strip text from a string by KalaMonkey

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