am trying to get the list of latest files in each dir(for each project) under a specific path ($output) , excluding a single dir OLD How can I frame a rule to achieve this?

file find rule date, file find rule date, file find rule date, site:perlmonks.org file find rule date

untested 

#!/usr/bin/perl --
use strict;
use warnings;
use File::Find::Rule qw/ find rule /;

Main( @ARGV );
exit( 0 );

sub Main {
    my @dirs = ProjectDirsInExcept( $output, 'OLD' );
    for my $dir (@dirs) {
        my ($file) = LatestFile($dir);
        print "$file\n";
    }
}

sub ProjectDirsInExcept {
    my ( $in, @except ) = @_;
    my @dirs = find(
        directory => not_name => \@except,
        maxdepth  => 1,
        in        => $output,
    );
    return @dirs;
}

sub LatestFile {
    my ($dir) = @_;
    my @files = find( file => maxdepth => 2, in => $dir );
    @files = map { $$_[0] }
      sort { $$b[1] <=> $$a[1] }
      map { [ $_, ( stat $_ )[9] ] } @files;
    return shift @files;
}
__END__

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In reply to Re: perl - File::Find::Rule to exclude a single dir by Anonymous Monk
in thread perl - File::Find::Rule to exclude a single dir by sravs448

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