$foo{bar}{baz} is the same as $foo{bar}->{baz} 
$ perl -le " $foo{bar}{baz} = 6; print $foo{bar}->{baz}; "
6

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See References quick reference and other links below like Data::Diver, Tutorials► Data Types and Variables ► Data Type: Array ► Data Type: Hash► References quick reference

More elaborate and coprehensive tutorial in http://learn.perl.org/books/beginning-perl/, Learn Perl in about 2 hours 30 minutes, perlintro, chromatics free book Modern Perl a loose description of how experienced and effective Perl 5 programmers work....You can learn this too.

In reply to Re: query on hash understanding by Anonymous Monk
in thread query on hash understanding by Ritz@Perl

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