Performing numeric compare in an if statement

while (<$FILE> {
 chomp;
 my ($number1,$number2,$number3,$number4) = split /\t/;
 print "$number4\n";

 if ($number4 == 1,2) {
     print "$number4 good\n";
 } else {
     print "$number4 bad\n";
 }

}

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I've correct result, but there are warnings

Useless use of numeric eq <==> in void context at ....
Argument "1,2" isn't numeric in numeric eq <==> at ....
1,2 good

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If I replace "==" with "eq" then i've warning and only 1 get printed. Expected output is 1,2 good

useless use of string eq in void context at ....
1 good

[download]

If I replace "eq" with "=" then i've no warning and only 1 get printed. Expected output is 1,2 good

1 good

Don't understand what's wrong. Please help!

In reply to Perl compare by waytoperl

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