Maybe it would be better if Perl has such magic precedence: 1) look at the operator, 2) if operator is for numerals (+,++) -> change operands to numerals ("4" -> 4 (change to bigint if used, otherwise to int), "40..(many)..0" -> 40..(many)..0 (change to bigint, if used, otherwise to int)). Now it seems that after looking to operator, if numeric, Perl change operands to int, then make operation, and later convert result to bigint (or not convert?).

In reply to Re^7: Perl can't make some easy arithmetics :( by rsFalse
in thread Perl can't make some easy arithmetics :( by rsFalse

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