I am trying to read the folder name from a text file and open the contents of the folder with the following- 
my $lines; my @lines;

# read (1 line only). FOLDERZ.
open INPUT, "<Output1.txt";

@lines = <INPUT>;
close INPUT;

foreach $lines (@lines){
 print "Line: ", $lines, "\n";

        my $linesA;   
       #my @linesA = "c\:\\Other\\renamedir\\FOLDERZ";
        my @linesA = "c\:\\Other\\renamedir\\$lines";
        foreach $linesA (@linesA){
                my $directory = "$linesA";
                print ("Folder: ", $directory, "\n");
                opendir (DIR, $directory) or die $!;
                         while (my $fldr = readdir(DIR)) {
                         print "Files & Folders: ", $fldr, "\n";   }
                closedir(DIR);
          }
        }

[download]
Getting the following error- 
Line: FOLDERZ

Folder: c:\Other\renamedir\FOLDERZ

Invalid argument at c:\temp\dir4E63.tmp\lineAF.pl line 22.
Press any key to continue . . .

[download]
Line 22: opendir (DIR, $directory) or die $!;

It works just fine if I replace $linesA with FOLDERZ. But doesn't like the scalar.
Please let me know.

In reply to Doesn't like a Scalar, as a folder path by ArifS

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