G'day Monks,

Why do you think someone would call the following a 'naive' solution?

Create sublists from an array of integers ,in increasing order:

Input: [ 1,2,3,4,5,6,7,8,3,5,6,3,8,1,7,8 ]
Desired Output: [[ 1, 2, 3, 4, 5, 6, 7, 8 ], [ 3, 5, 6 ], [ 3, 8], [ 1,7,8]]
my @array1 = (1,2,3,4,5,6,7,8,3,5,6,3,8,1,7,8); my @newarray; my @tmparray; for (0..$#array1) { if ($_> 0 && $array1[$_] < $array1[$_-1]) { push (@newarray, [@tmparray]); undef(@tmparray); } push (@tmparray, $array1[$_]); } push (@newarray, [@tmparray]) if defined @tmparray;

Then from the output generated sort items in a single array:
My assumption was that I no longer had @array1 to work with and had to create the final sorted array from @newarray.

Input: [[ 1, 2, 3, 4, 5, 6, 7, 8 ], [ 3, 5, 6 ], [ 3, 8 ]]
Desired Output [ 1,1,2,3,3,3,4,5,5,6,6,7,7,8,8,8 ]
my @array3; for (@newarray) { push @array3, @$_; } @array3 = sort @array3;
Also, is this wrong to say in this particular case the complexity is O(n) disregarding the complexity of sort?

FYI: This was in an interview...


In reply to Spliting array into nested sequential arrays by Hameed

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