Hello rocketperl,

Your regex is pretty close to being correct. Just two tweaks needed:

  1. You need to count the capture ([A-Z]) in the total. So, to get 5 or more, you need m/([A-Z])\g2{4,}/.

  2. To see the repeated letters, you need another capture:

    #! perl
use strict;
use warnings;
use constant MIN_MATCHES => 5;

my %sequ =
(
    1 => 'abcXXXXXef',
    2 => 'abcYYYYYYef',
    3 => 'abZZZZef',
);

my $match_at_least = MIN_MATCHES - 1;

for my $k (1 .. 3)
{
    if (my @matches = $sequ{$k} =~ m/(([A-Z])\g2{$match_at_least,})/)
    {
        print "Match: $matches[1] in $matches[0] \n";
    }
}

    [download]

    Output:

    16:47 >perl 1069_SoPW.pl
Match: X in XXXXX
Match: Y in YYYYYY

16:47 >

    [download]

    Note that capture groups are numbered according to the position of the left parenthesis, so the whole sequence of repeated characters is \g1 and the first character is \g2. I have also removed the /g modifier to keep things simple.

Hope that helps,

Athanasius <°(((>< contra mundum Iustus alius egestas vitae, eros Piratica,

In reply to Re: Backreference regex help by Athanasius
in thread Backreference regex help by rocketperl

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