There is also a possible precedence issue with your statement. If you meant:

$c = &func();
$c ? say "$c found!" : say "None!";

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and not 
$c = (&func() ? say "$c found!" : say "None!");

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then you got it wrong. ?: has a higher precedence than assignment (see perlop), so the ternary operator binds tighter to its operands than does the assignment operator. The ternary operator is handled first, then the assignment operator. To illustrate, try 
perl -Mstrict -E 'sub func {5}; my $c; my $results = ( $c=func() ? 1 :
+ 2); say $c, "\t", $results'

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and 
perl -Mstrict -E 'sub func {5}; my $c; my $results = ( $c=func()) ? 1 
+: 2; say $c, "\t", $results'

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--MidLifeXis

In reply to Re: Why so strict? by MidLifeXis
in thread Why so strict? by mikeh123

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