I had a task for myself: given interval and a number, find if it is before, in, or after an interval? It can be find using two basic comparisons. But here I tried to use ternary <=>:
use POSIX;
while(<DATA>){
chomp;
($l, $r)=split/ /;
printf "[%2d %2d] ", $l, $r;
for $i(-9..10){
$i or print "|";
printf "%2d ", floor (($i - $l ) / ($r - $l +1 )) <=> 0
}
print "\n"
}
__DATA__
1 4
2 5
3 7
0 3
-1 5
-8 -2
OUTPUT:
[ 1 4] -1 -1 -1 -1 -1 -1 -1 -1 -1 |-1 0 0 0 0 1 1 1 1 1 1
[ 2 5] -1 -1 -1 -1 -1 -1 -1 -1 -1 |-1 -1 0 0 0 0 1 1 1 1 1
[ 3 7] -1 -1 -1 -1 -1 -1 -1 -1 -1 |-1 -1 -1 0 0 0 0 0 1 1 1
[ 0 3] -1 -1 -1 -1 -1 -1 -1 -1 -1 | 0 0 0 0 1 1 1 1 1 1 1
[-1 5] -1 -1 -1 -1 -1 -1 -1 -1 0 | 0 0 0 0 0 0 1 1 1 1 1
[-8 -2] -1 0 0 0 0 0 0 0 1 | 1 1 1 1 1 1 1 1 1 1 1
For example I can use the answer as the index of list of 3 elements:
qw(in after before)[find($left, $right, $n)]
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