In my opinion, after "($key, $value)" are assigned to "()" and list becomes "(undef, undef)", scalar context takes only the last element of the list, that means 2nd "undef". Am I wrong?

Compare:

$ perl -E 'say scalar ( ($a, $b) = () )'
0
$ perl -E 'say scalar ( ($a, $b) = (undef, undef) )'
2

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In reply to Re: each %hash: scalar context of list (undef, undef) is false by Anonymous Monk
in thread each %hash: scalar context of list (undef, undef) is false by rsFalse

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