Prototypes alter how a function call is parsed, but need to do so at compile time. So the interpretation of the function call depends on whether List::BinarySearch has already been loaded or not at the time your call to it is compiled.

Because you don't know whether or not List::BinarySearch, it is safer to avoid the issue by bypassing prototypes (which is what the & does).

toby döt ink

In reply to Re^3: List::BinarySearch and conditional tests with Test::More by tobyink
in thread List::BinarySearch and conditional tests with Test::More by glasswalk3r

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