Hi Monks

This is probably really simple but I cannot for the life of me find any material on this.

I need to write a script that allows someone to enter a reference code when prompted, I already have this but.... I need the script to search a directory full of other directories for a file containing that string which I assume I can use grep for, the difficult bit, for me, is I want to grep the file and then read it into an array like this 
pseudo code:
#!/usr/bin/perl -w

use strict;
use warn;

my $REF;
my @LINES;
my $DPT_DIR=/shares/test/PPdir/

print "ENTER REF NUMBER";
chomp($REF = <>);

grep "$REF" */*.dpt
open my $FH, '<', *.dpt file grep has found
chomp(@LINES, $FH);
close $FH

[download]

Any help would be greatly appreciated.

Thanks

Jim

EDIT: Apologies it has be come apparent to me this isn't very clear, I don't need the list of files in an array but the contents of a single file. 
Linux grep:

#grep -l ABC123 */*.dpt
lloydf/test.dpt <-- I need to read this file.

[download]
there are going to be several *.dpt all containing different refs which is why I need to do a grep/find

In reply to Grep file out of directory and read into array by Jalcock501

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