Actually, exists tests if the element is present. Even if the element exists, the value of the element could still be undef.
Note that defined($array[$i]) will cause the element at index $i to be created. Likewise, defined($array{$k}) will create an element referred by key $k. In both cases, the new element with have the value undef.
This "auto-vivification" may have undesirable side effects. This is most likely to become a problem where a hash is being used to hold options or named parameters. Often times, the absence of an option or parameter has a different meaning than when present with no value specified (ie, value is undef).
When in doubt, it is generally better to test for existence then for a defined value:
if (exists $params{'foo'}) { if (defined $params{'foo'}) { ...; } else { ...; } } else { ...; }
In reply to Re^3: why can't compare a variable with undef directly?
by RonW
in thread why can't compare a variable with undef directly?
by Anonymous Monk
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