Just because I wanted to see what the compress and decompress subs looked like :) 

#!/usr/bin/perl

# https://perlmonks.org/?node_id=1233613

use strict;
use warnings;
use re 'eval';

my %huffman = (         # from LanX https://perlmonks.org/?node_id=111
+00047
  ""    => "0110",
  "2"   => 1001000,
  "24"  => "0101000",
  "246" => 101111110,
  "247" => 101111011,
  "248" => 101111010,
  "249" => 110010100,
  "25"  => 1001010,
  "257" => 101111001,
  "258" => 101111101,
  "259" => 101111000,
  "26"  => 1011100,
  "268" => 101111100,
  "269" => 101111111,
  "27"  => 1001011,
  "279" => 110010101,
  "28"  => 1001001,
  "29"  => 11101011,
  "3"   => 111011,
  "35"  => "010111",
  "357" => 11001011,
  "358" => 11001001,
  "359" => 10111011,
  "36"  => 110000,
  "368" => 11101010,
  "369" => 10111010,
  "37"  => 110001,
  "379" => 11001000,
  "38"  => 110011,
  "39"  => "010110",
  "4"   => 10110,
  "46"  => "00100",
  "468" => "0101011",
  "469" => "0101010",
  "47"  => "01110",
  "479" => "0101001",
  "48"  => "01111",
  "49"  => "00101",
  "5"   => "0100",
  "57"  => 10000,
  "579" => 1110100,
  "58"  => 11100,
  "59"  => 10001,
  "6"   => 1010,
  "68"  => 11011,
  "69"  => 11010,
  "7"   => "000",
  "79"  => 10011,
  "8"   => 1111,
  "9"   => "0011",
  );

my %tohuff = map { $_, $huffman{ ('23456789' & tr/01/ ?/r) =~ tr/ //dr
+ } }
  grep !/11/ && tr/1// <= 3, glob '{0,1}' x 8;
my @allcodes = map "$huffman{$_}(?{$_})", keys %huffman;
my $fromhuff = do { local $" = '|'; qr/(?:@allcodes)/ };

sub compress
  {
  my $coded = '';
  for ( shift =~ /(.*)\n/g )
    {
    my @lookup = (0) x 123;
    @lookup[ unpack 'C*', $_ ] = (1) x length;
    for( my $group = 35; $group < 123; $group += 10 )
      {
      $coded .= $tohuff{ join '', @lookup[$group .. $group + 7] };
      }
    }
  return pack 'b*', $coded;
  }

sub decompress
  {
  my $decoded = '';
  my $decade = 33;
  local $_ = unpack 'b*', shift;
  while( /$fromhuff/g )
    {
    $decoded .= pack 'C*', map $decade + $_, split //, ($^R // '');
    ($decade += 10) >= 123 and $decade = 33, $decoded .= "\n";
    }
  return $decoded =~ s/^.+\z//mr;
  }

my $input = '';
for (1 .. 100)
  {
  for (my $x=0; $x<90; $x+=10)
    {
    my @c;
    push(@c, int (rand(10)+$x));
    push(@c, int (rand(10)+$x));
    push(@c, int (rand(10)+$x));
    push(@c, int (rand(10)+$x));
    @c = sort{$a<=>$b}@c;
    for (my $i = 1; $i < @c; $i++)
      {
      $input .= chr(33+$c[$i]) if $c[$i] != $c[$i-1] && $c[$i] != $c[$
+i-1]+1;
      }
    }
  $input .= "\n";
  }

#use Data::Dump 'dd'; dd $_ for $input =~ /.*\n?/g;
print "\n     input length ", length $input, "\n";

my $compressed = compress($input);
my $compressedlength = length $compressed;
print "compressed length $compressedlength\n";
my $restored = decompress($compressed);
if( $input eq $restored )
  {
  printf "\nMatched, compression ratio = %.1f%%\n",
    100 * (1 - length($compressed) / length($restored));
  }
else
  {
  print "----------------------------------------failed\n";
  use Data::Dump 'dd'; dd $_ for $restored =~ /.*\n?/g;
  }

[download]

Typical output: 

     input length 1512
compressed length 557

Matched, compression ratio = 63.2%

[download]

In reply to Re^8: Data compression by 50% + : is it possible? by tybalt89
in thread Data compression by 50% + : is it possible? by baxy77bax

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