Does "split() no longer modifies @_" mean that it will not return the output of its call to the variable @_? As in, split(\/t\, $line) will not work, but my @array = split(\/t\, $line) will work?

Yes, that's it. In your first piece of code, you were using split in "void context" because you weren't doing anything with the return value, in which case Perl before v5.12 used to store split's return value in the @_ variable, which is why you could access it via $_[0] etc. That is no longer the case, and you need to use split's return value explicitly, such as by storing it in an array, like you did in your second piece of code.

In reply to Re^3: What is the logical error here (Fixed, but I want to understand) by haukex
in thread What is the logical error here (Fixed, but I want to understand) by hghosh

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