call($x++, $x++) works in an unsurprising manner.
$ perl -e'$x=3; CORE::say for $x++, $x++'
3
4
I think you're referring to the oddities of call(++$x, ++$x).
$ perl -e'$x=3; CORE::say for ++$x, ++$x'
5
5
or
$ perl -e'$x=3; CORE::say for $x, $x++'
4
3
These occur because $x and ++$x (and --$x) add the scalar $x itself to the stack rather than a copy. $x++ (and $x--) necessarily add a copy of the original value.
Well, the problem is related to the scalars themselves being on the stack, so the explanations are indeed related. But that's just the precondition for the problem, not the answer itself.
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