>> min(int(9*$x),8)

When number of intervals vary (not only 9), then this looks more general:
my $intervals = 9; min( int( $intervals * $x ), $intervals - 1 )
or:
my $intervals = 9; int( $intervals * $x ) - int $x

In reply to Re^3: sub as mathematical function by rsFalse
in thread sub as mathematical function by Anonymous Monk

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