I already updated my post to say that you are probably right, but I'll say it again, straighter to the point: B::Deparse seems to confirm your interpretation as if (1) {BLOCK} is turned into do {BLOCK} (with BLOCK empty in rsFalse's example), and if (0) {} is turned into 0. So in the first case the if is optimized to return the value of the block, and in the second case the value of the EXPR.

++ to you obviously :)

In reply to Re^2: printing unitialized value of the 'do BLOCK' by Eily
in thread printing unitialized value of the 'do BLOCK' by rsFalse

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