One could say that vec produces a packed little-endian integer. The bytes are ordered from most significant to least significant. In other words, 

my $m0; vec($m0, $_, 1) = 1 for 0,2,8,9,10;

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is equivalent to 

my $m0l; vec($m0l, $_,   1) = 1 for 0,2;
my $m0h; vec($m0h, $_-8, 1) = 1 for 8,9,10;
my $m0 = $m0l . $m0h;

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Option 1: Reverse the order of the bytes then convert the bytes to binary one by one. 

unpack "B16", scalar reverse $mo

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Option 2: Unpack the bytes into a number, and print the binary representation of that number 

sprintf "%016b", unpack "v", $m0

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In reply to Re: Displaying bit-vectors with Most Significant Bits to the left? by ikegami
in thread Displaying bit-vectors with Most Significant Bits to the left? by LanX

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