Yet another solution (:

You can eval random code inside (?{ }) and use result with variable $^R

$bar =~ s#\d{2}(?{ $& * 5})#<td>$^R</td>#gms;

More information:

perldoc -v '$^R'
perldoc -v '$&'
perldoc perlre

[download]

And I want to point, that you don't need to capture whole match. It will already situated in $&

P.S.

I should have said, that there is global performance penalty for using $& somewhere in your code. It was fixed only in 5.020

Please read following documentation for more information:

perldoc perlfaq6
perldoc perlvar

[download]

In reply to Re: Side effects of an /e modifier by k-mx
in thread Side effects of an /e modifier by timpoiko

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