I am converting IBM mainframe files and I have had a lot of luck converting binary fixed length files that have COMP-3 fields using the unpack ("H*",$_) setup, however I am having an issues with a file that has binary fields. Here is the input record layout:

01 EXTRACT-REC-IN.
03 KEY-DATA.
05 FIELD1 PIC 9(5) VALUE 0 BINARY.
05 FIELD2 PIC 9(4) VALUE 0 BINARY.
05 FIELD3 PIC 9(4) VALUE 0 BINARY.
05 FIELD4 PIC 9(8) VALUE 0 BINARY.
05 FIELD5 PIC 9(4) VALUE 0 BINARY.
03 DATA.
05 FIELD6 PIC S9(04) VALUE 0 COMP.
05 FILED7 PIC S9(15)V99 VALUE 0 COMP-3.
05 FIELD8 PIC S9(15)V99 VALUE 0 COMP-3.

How do I unpack these BINARY fields in the KEY-DATA Section? See my code below as I have tried to use I1 in unpack section but it gives me 2936078336 when I am expecting to see 425 for FIELD1 Any help is appreciated!


#! /usr/bin/perl -w
@ARGV == 1 or die "usage: $0 in_filename out_filename\n";
my $in_filename = shift;

#set infile to binary mode
open INFILE, '<:raw', $in_filename or die "can't open $in_filename: $!
+";
binmode(INFILE);

#open OUTFILE, '>', $out_filename or die "can't open $out_filename: $!
+";

# record length is 34
$/ = \34;

#map input file to process integers

while ( <INFILE> ) {
    my($f1)
       = unpack ("I1",$_); 

#format variables
     
     my $f1p = sprintf("%d", $f1);  
      


   
#write record to file
     
     print "$f1p\n";
            
                                                     
     }

                     
 close INFILE;

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In reply to Perl Unpack Cobol Binary File and Fields by dbarkho14

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