FWIW, here's another variation. It has the advantage of producing empty strings rather than undefined values for absent pattern elements, so no need for a conversion step. It also has the advantage, if such it be, of not using named captures with the possible overhead of tied-hashery. It passes all tests above. 

$string =~ m{
    \A
    ([[:alnum:]]+?) (?= (?: \d+ [[:upper:]]{0,2})? \z)
    (\d*) ([[:upper:]]?) ([[:upper:]]?)
    \z     
    }xms;

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Give a man a fish:   <%-(-(-(-<

In reply to Re^2: Question on Regular Expression by AnomalousMonk
in thread Question on Regular Expression by sjain

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