Thanks.

Note that not all configurations of the puzzle are solvable. My check for  $inversions % 2 == 0 makes sure we get a solvable configuration. I don't see anything comparable in your code, though it could be I'm just not seeing it.

$_="msh210";$"=$\;@_=@{[split//,uc]}[2,0];$_="@_$\1";$\=$/;++$_[0]for$...1;print lc substr crypt($_,"@_"),1,6

In reply to Re^2: The 15 Puzzle by msh210
in thread The 15 Puzzle by msh210

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