Perl doesn't have a destructuring assignment because it's a workaround for the inability to return multiple values that Perl has naturally.

[ a, b, ...rest ]                    // ES6
{ a:4, b:5, ...rest }                // ES6
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is the same as

[ $a, $b, @rest ]                    # Perl
{ a=>4, b=>5, %rest }                # Perl
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Alternatively, you could argue that ... is known as ->@* and ->%* in Perl.

[ a, b, ...[ c, d ] ]                // ES6
{ a:4, b:5, ...{ c:6, d:7 } }        // ES6
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is the same as

[ $a, $b, [ $c, $d ]->@* ]           # Perl
{ a=>4, b=>5, { c=>6, d=>7 }->%* }   # Perl
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Update: Changed the layout of the answer.