> But $m is a reference

yes and no ...

In proper CS speak it's a "call by reference", in Perl we tend to use "alias" for such passing.

But in Perl speak it's not a "reference" like created by the reference operator \

see also https://perldoc.pl/perlglossary.html#call-by-reference

Cheers Rolf
(addicted to the Perl Programming Language :)
Wikisyntax for the Monastery

In reply to Re^2: Ternary Quizical behaviour? by LanX
in thread Ternary Quizical behaviour? by bliako

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