> put into a slot of a symbol table entry.

An alias is always a variable true, that's an obvious no-brainer.

But typeglob mechanisms are only a part of the way to create them.

Especially in for my $a (@a) { ... } there is no symbol table entry like you claimed. my $a is a private variable and an alias.

And newer Perl versions allow activating the feature for refaliasing too, again no symbol table.

Cheers Rolf
(addicted to the Perl Programming Language :)
Wikisyntax for the Monastery

In reply to Re^12: Shouldn't references be readonly? by LanX
in thread Shouldn't LITERAL references be readonly? (updated) by LanX

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