Using int will truncate so if the result, due to the inexact way a computer will represent 0.0001, is, say, 6504.9999997 it will end up as 6504. This seems to work.

johngg@abouriou:~/perl/Monks$ perl -E 'say 0.6505 / 0.0001;'
6505

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Cheers,

JohnGG

In reply to Re: finding the correct integer by johngg
in thread finding the correct integer by YarNik

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