> Is it because the procedure I'm writing is always called by the object handle? Does that make it NOT the same as the built-in function?

Exactly, because the method and the builtin are in different namespaces aka packages.

The method call -> will look into the "STASH" of MyPackage:: while calls to builtins are resolved in CORE:: (resp. CORE::GLOBAL ) °

You can actually override (some) builtin functions, but that's not what is happening here.

EDIT

°) see https://perldoc.perl.org/perlsub#Overriding-Built-in-Functions for details on real overriding

Cheers Rolf
(addicted to the Perl Programming Language :)
Wikisyntax for the Monastery

In reply to Re: Override built-in functions? by LanX
in thread Override built-in functions? by TorontoJim

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