The data you have is JSON. And a module such as JSON has decode_json to convert it to a Perl data structure. Alternatively, if you don't want to install JSON, Perl ships with JSON::PP, which is a drop-in replacement (or fall-back).

#!/usr/bin/env perl use strict; use warnings; use JSON qw(decode_json); my $json = do { local $/ = undef; <DATA>; }; my $data = decode_json($json); foreach my $element (@{$data->{'genres'}}) { print "id: $element->{'id'}, name: $element->{'name'}\n"; } __DATA__ { "genres": [ { "id": 28, "name": "Action" }, { "id": 12, "name": "Adventure" }, { "id": 16, "name": "Animation" }, { "id": 35, "name": "Comedy" }, { "id": 80, "name": "Crime" }, { "id": 99, "name": "Documentary" }, { "id": 18, "name": "Drama" }, { "id": 10751, "name": "Family" }, { "id": 14, "name": "Fantasy" }, { "id": 36, "name": "History" }, { "id": 27, "name": "Horror" }, { "id": 10402, "name": "Music" }, { "id": 9648, "name": "Mystery" }, { "id": 10749, "name": "Romance" }, { "id": 878, "name": "Science Fiction" }, { "id": 10770, "name": "TV Movie" }, { "id": 53, "name": "Thriller" }, { "id": 10752, "name": "War" }, { "id": 37, "name": "Western" } ] }

This produces:

id: 28, name: Action id: 12, name: Adventure id: 16, name: Animation id: 35, name: Comedy id: 80, name: Crime id: 99, name: Documentary id: 18, name: Drama id: 10751, name: Family id: 14, name: Fantasy id: 36, name: History id: 27, name: Horror id: 10402, name: Music id: 9648, name: Mystery id: 10749, name: Romance id: 878, name: Science Fiction id: 10770, name: TV Movie id: 53, name: Thriller id: 10752, name: War id: 37, name: Western

A foreach loop is useful here, as described in perlintro or perlsyn. Dealing with complex data structures is covered in Intermediate Perl (OReilly), in perlreftut, perlref, perldsc, and perllol.


Dave


In reply to Re: How can I convert this raw data to a hash? by davido
in thread How can I convert this raw data to a hash? by SergioQ

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