> the global substitution took care of it in one pass
not in scalar context which is enforced by the boolean context of the while condition.
see s///g in perlop, perlre , perlretut
update
Global matching
In scalar context, successive invocations against a string will have //g jump from match to match, keeping track of position in the string as it goes along. You can get or set the position with the pos() function.
update
I was wrong the scalar thing is only valid for m//g , s///g just returns the number of all substitutions
DB<112> $_ = "a a a"
=> "a a a"
DB<113> scalar s/a/x/g
=> 3
update
See this example in perlop for a similar use case
1 while s/(\d)(\d\d\d)(?!\d)/$1,$2/g;
But without knowing Foo and Bar we can only speculate.
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