There are two uses for '...' - as:

  1. part of an expression - see Range Operators
  2. statement on its own - equivalent to die "Unimplemented"; - see The Ellipsis Statement

And so...

I don't understand why '...; print 1;' exits after ellipsis and not proceeds to print (v5.28). Can someone explain?

The sequence ...; print 1; does not proceed to print, because it dies before the print, just at the ...;

I understand why 'print ...' breaks: because it makes syntax error.

Yes. Because it is not a statement on its own, it is interpreted as the infix range operator, which lacks arguments - so "syntax error".

perl -le'print map{pack c,($-++?1:13)+ord}split//,ESEL'

In reply to Re: Question about ellipsis statement '...' by shmem
in thread Question about ellipsis statement '...' by rsFalse

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