Print rounds down

As a generalization this is not true.
Even when it is true for some value $x, it will be untrue for -$x.
However, there are times when print() rounds up for positive values.

Consider the following (perl-5.32.0, nvtype is "double"):
use strict; use warnings; my $d = 0.4444444444444446; printf "%a\n", $d; print "$d\n"; print "print() has rounded upwards\n" if "$d" > $d; __END__ Outputs: 0x1.c71c71c71c71fp-2 0.444444444444445 print() has rounded upwards
And how do I calculate the value of this "epsilon" that is being mentioned ?

Cheers,
Rob

In reply to Re^4: what did I just see..? by syphilis
in thread what did I just see..? by ishaybas

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