I don't understand that first part. Wouldn't a shallow copy by faster for large arrays, since the data isn't actually being copied?

And "changes to the array"... oh, right, as opposed to changes to the elements of the array? I think I get it. That should be fine in this case, since I never actually wanted the original array and won't use it again. Good to know in other situations, though.

In reply to Re^5: Referencing the locals by Chuma
in thread Referencing the locals by Chuma

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